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Please try the request again. Python functions with multiple parameter brackets Why didn't Dumbledore make a sound when he appeared on Privet Drive? Your cache administrator is webmaster. All rights reserved.

ABOUT CHEGG Media Center College Marketing NEW Privacy Policy Your CA Privacy Rights NEW Terms of Use General Policies Intellectual Property Rights Investor Relations Enrollment Services RESOURCES Site Map Mobile Publishers The system returned: (22) Invalid argument The remote host or network may be down. Maybe something wrong with my solution. Question: Consider the initial-value problem y' + exy = f{x)...

Employee is not interested in career development more hot questions question feed about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Please try the request again. This puts a unique condition on $y$ and in particular forces it to be very close to $x$ in magnitude but $y < 0$.

All rights reserved. Your cache administrator is webmaster. ABOUT CHEGG Media Center College Marketing NEW Privacy Policy Your CA Privacy Rights NEW Terms of Use General Policies Intellectual Property Rights Investor Relations Enrollment Services RESOURCES Site Map Mobile Publishers When I solve, I'm just have one solution, so I cannot find other.

Not the answer you're looking for? Browse hundreds of Advanced Math tutors. Generated Sat, 18 Mar 2017 14:58:46 GMT by s_hv1050 (squid/3.5.23) ERROR The requested URL could not be retrieved The following error was encountered while trying to retrieve the URL: http://0.0.0.7/ Connection Your cache administrator is webmaster.

share|cite|improve this answer answered May 20 '12 at 11:47 Derek Allums 1,6282728 add a comment| up vote 2 down vote As of maximum value of $f(x,y)$ $$\frac{x^3+y^3}{2} \geq {\left(\frac{x+y}{2} \right)}^3 \geq How to deal with an inappropriate greeting in an email? Best answer 100% (1 rating) Get this answer with Chegg Study View this answer OR Find your book Find your book Need an extra hand? y = e?ex + 2 What is the solution when f(x) = 0?

Notice then that when you plug these numbers into $f(x,y)$, you get ("large" means large absolute magnitude) $$f(x,y) = e^{xy} = e^{(\text{large positive)} \cdot (\text{large negative})} = e^{\text{large negative}} \approx 0.$$ The system returned: (22) Invalid argument The remote host or network may be down. Your cache administrator is webmaster. y = e?ex x 1 dt 0 + 2 What is the solution when f(x) = 0?

asked 4 years ago viewed 3952 times active 1 year ago 15 votes · comment · stats Related 2When $\min \max = \max \min$?2Find min & max of $a(b-c)^n+b(c-a)^n+c(a-b)^n$ where $a Here is my solution: $$f(x,y) = e^{xy}$$ $$g(x,y) = x^3+y^3-16$$ $t(x,y) = f(x,y) + \lambda*g(x,y)$ So we will have three equations by Lagrange Multiplier: $$(1) y*e^{xy} + 3*\lambda*x^2 = 0$$ $$(2) But at min case, I don't have any idea how to solve by Lagrange Multiplier –hqt May 20 '12 at 11:03 1 Yes I know that , I wrote this Please helps me.

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This is why there is no other critical point corresponding to a relative minimum: there is no relative minimum. Too much whitespace between two digits when using \pi in first argument of \SI{}{} Magic the Gathering: Friends or Foes? The system returned: (22) Invalid argument The remote host or network may be down.

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What is the solution when f(x) = ex? To see if it's a min or max, you need to do some more work, though (see the last post in that thread). In your case, as seems to be confirmed when this question was asked on this site, you only have one critical value. What is the solution when f{x) = 0?

Thanks Show transcribed image text Consider the initial-value problem y' + exy = f{x), y{0) = 1. Browse other questions tagged analysis inequality or ask your own question. y = 4 Show transcribed image text Consider the initial-value problem y' + exy = f(x), y(0) = 1. Bash script for deleting and inserting lines How to suppress the bash execution trace (set -x) from the outside of the script it is set in?